Question

Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden

Answer 1

Step-by-step explanation:

$\huge{\underbrace{\overbrace{\mathfrak{\pink{Answer:}}}}}$

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

Answer 2

$\huge\mathrm\pink{Solution:}$

$\large\sf\red{Given}$

Half the perimeter of a rectangular garden = 36 m

so, $\sf\frac{2(l+b)}{2}$ = 36

(l + b) = 36

$\large\sf\red{Given}$

The length is 4 m more than its width.

Let width = x

And length = x + 4

Substituting this in eq(1), we get;

x + x + 4 = 36

2x + 4 = 36

2x = 32

x = 16

Therefore, the width is 16 m and the length is 16 + 4 = 20 m.

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$\large\tt\purple{@SwagHero❤}$