Question

half the perimeter of a rectangular Garden whose length is 4 metre more than its width is 36 metre find the dimension of the garden​

Answer 1

Answer:

20 meters

Step-by-step explanation:

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

Answer 2

Given

• Perimeter of the rectangular garden = 36 m
• Length of the rectangular garden is 4 metre more than its width.

To find

• Dimensions of the rectangular garden

Solution

Let the breadth of the rectangular garden be x m and the length be (x + 4) m.

Using formula,

Perimeter of rectangle = 2(l + b)

where,

• l = length of the rectangle
• b = breadth of the rectangle

Substituting the values,

⟶ 2(x + x + 4) = 36

But according to the question, Half of the perimeter = 36 m. So,

⟶ 2(2x + 4)/2 = 36

⟶ (2x + 4)/2 = 36/2

⟶ (2x + 4)/2 = 18

⟶ 2x + 4 = 18 × 2

⟶ 2x + 4 = 36

⟶ 2x = 36 - 4

⟶ 2x = 32

⟶ x = 32/2

⟶ x = 16

The value of x = 16

Therefore, Dimensions of the rectangular garden :-

• Length of the rectangular garden = x + 4 = 16 + 4 = 20 m
• Breadth of the rectangular garden = x = 16 m

______________________________

Let's verify :-

⟶ 2(l + b)/2

⟶ 2(20 + 16)/2

⟶ 2(36)/2

⟶ 36 m

Hence, verified.