Question

Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is
36 m. Find the dimensions of the garden.​

Answer 1

Step-by-step explanation:

let w=x

l=x+4

1/2(perimeter)=36

1/2(2(l+b))=36

(l+b)=36

x+x+4=36

2x=32

x=16

w=16

l=20

Answer 2

ANSWER:-

Given:-

half the perimeter of a rectangular garden = 36 m

so, 2(l + b)/2 = 36

(l + b) = 36 ..(1)

the length is 4 m more than its width.

Solve:-

Let width = x

And length = x + 4

Substituting this in eq(1), we get;

Formula:-

$\mathrm{ \to \: x + x + 4 = 36}$

$\mathrm{ \to 2x + 4 = 36}$

$\mathrm{ \to 2x = 32}$

$\mathrm \orange{ \implies x = 16}$

Therefore:-

the width is 16 m and the length is 16 + 4 = 20m