Math, asked by bhavitadalalw, 5 months ago

Half the perimeter of a rectangular garden, whose length is 4 m more than its width,
36 m. Find the dimensions of the garden. ​

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Answered by kdmondal1955
0

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Answered by Anonymous
247

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  • Let the width of the garden =x meter
  • Let the width of the garden =x meterThen length=(x+4) meter

  • Let the width of the garden =x meterThen length=(x+4) meterHalf perimeter =36 m

  • Let the width of the garden =x meterThen length=(x+4) meterHalf perimeter =36 mSo perimeter of garden =(2×36)=72 meters

  • Let the width of the garden =x meterThen length=(x+4) meterHalf perimeter =36 mSo perimeter of garden =(2×36)=72 metersAccording to the question

  • 2(l+b)=72

2(l+b)=72⇒2(x+x+4)=72

2(l+b)=72⇒2(x+x+4)=72⇒2x+2x+4=74⇒4x=64⇒x=16 meters

2(l+b)=72⇒2(x+x+4)=72⇒2x+2x+4=74⇒4x=64⇒x=16 metersHence,the width of the garden =16 meters

2(l+b)=72⇒2(x+x+4)=72⇒2x+2x+4=74⇒4x=64⇒x=16 metersHence,the width of the garden =16 metersThe length of the garden =(16+4)=20 meters.

I hope it helps u ✌️..

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