Math, asked by noor407, 3 months ago

Half the perimeter of a rectangular garden whose length is 6 m more than its width is 36 m , The dimensions of the garden are 

Answers

Answered by SarcasticL0ve
1

Given:

  • Length of rectanglular garden is 6 m more than its breadth.
  • Half of perimeter of the rectanglular garden is 36 m.

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To find:

  • Dimensions of garden?

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Solution:

Let Breadth of rectanglular garden be x m

Then, Length of rectanglular garden is (x + 6) m

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\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large (x + 6) m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large x m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

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We know that,

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\star\;{\boxed{\sf{\purple{Perimeter_{\;(rectangle)} = 2(l + b)}}}}\\ \\

\underline{\sf{\bigstar\; According\;to\;the\; Question\;:}}\\ \\

Half of perimeter of the rectanglular garden is 36 m

:\implies\sf \dfrac{2(l + b)}{2} = 36\\ \\

:\implies\sf l + b = 36\\ \\

Here,

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  • Length, l = x m
  • Breadth, b = (x + 6) m

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:\implies\sf x + (x + 6) = 36\\ \\

:\implies\sf 2x + 6 = 36\\ \\

:\implies\sf 2x = 36 - 6\\ \\

:\implies\sf 2x = 30\\ \\

:\implies\sf x = \cancel{ \dfrac{30}{2}}\\ \\

:\implies{\boxed{\sf{\pink{x = 15}}}}\;\bigstar\\ \\

Therefore,

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  • Breadth of rectanglular garden, x = 15 m
  • Length of rectanglular garden, (x + 6) = 21 m

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\therefore\;{\underline{\sf{Hence,\; Dimensions\;of\;rectangular\;garden\;is\;21\;m\;and\;15\;m\: respectively.}}}

Answered by Anonymous
2

Given ,

  • The half of the perimeter of rectangle is 36 m

  • The length of rectangle is 6 m more than its width

∴Perimeter of rectangle = 2 × 36 i.e 72 m

Let , the breadth of rectangle be " x "

Then , length = " x + 6 "

We know that , the perimeter of rectangle is given by

  \boxed{ \tt{Perimeter = 2(length + breadth)}}

Thus ,

72 = 2(x + 6 + x)

36 = 2x + 6

30 = 2x

x = 30/2

x = 15 m

Therefore , the length and breadth of rectangle are 21 m and 15 m

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