Question

Half the perimeter of a rectangular garden whose length is 12m more than its width, is 60m. Find the dimensions of the garden.
Please answer...

Answer 1

Answer:

Step-by-step explanation:

half the perimeter = 60m

therefore, perimeter of the garden = 60 x 2

perimeter of a rectangle = 2(length + breadth)

ie, 2(l + b) = 2 x 60

hence, l + b = 60

it is given length is 12m more than width

let width = x

then length = 12 + x so using the first equation, x + 12 + x = 60

12 + 2x = 60

2x = 60-12 = 48

x = 24 m

width = 24m and length = 12+24 =36m

Answer 2

$\bf{\huge{\underline{\boxed{\sf{\blue{Answer:}}}}}}$

Given that :-

Half the perimeter of a rectangular garden whose length is 12m more than its width, 60m.

To find :-

The dimensions of the garden.

_____________________________________

According to question:

Perimeter of a rectangle = 2(l + b)

Therefore half of the perimeter = 2(l + b)/2

= Length + Breadth

$\boxed{Now,}$

Let the breadth (width) of the rectangle be x.

Therefore it's length = x + 12

Length + Breadth = 60m

x + 12 + x = 60m

2x + 12 = 60m

2x = 60 - 12

2x = 48m

x = 48/2

x = 24m

Hence, dimensions of the rectangular garden :-

Length = x + 12 = 24 + 12 = 36m

Width = x = 24m

$\huge{\sf{\boxed{\boxed{Verification:-}}}}$

If half of the perimeter is 60m, then full perimeter = 60 × 2 = 120m

Perimeter of the rectangular garden = 2 (24 + 36)

= 2 × 60

= $\bold{120m\:hence\:verified}$