Question

half the perimeter of rectangle Garden whose length is 4m more than its width in 36 metre find the dimension of Garden by linear equation in two variable​

Answer 1

Answer:

Required numeric value of length of the garden is 20 m and width is 16 m.

Step-by-step-explanation:

It is given that half ( or 1 / 2 ) of the perimeter of rectangle garden whose length is 4m more than its width is 36 m.It simply means that the length of garden is 4 m more than its width and perimeter of that same garden is 36 m.

According to the question :

• Length of garden = Width of garden + 4 m.

• 1 / 2 of perimeter = 36 m

Let the length of garden be a m and width of garden be b m, where m represents that unit i.e. metre.

= > Length of garden = Width of garden + 4 m

= > a m = b m + 4 m

= > a m = ( b + 4 ) m

= > a = b + 4

= > a - b = 4 ... ( 1 )

= > Half of the perimeter = 36 m

From the properties of rectangle,

• Perimeter of rectangle = 2( length + width )

= > 1 / 2 x 2( a m + b m ) = 36 m

= > ( a + b ) m = 36 m

= > a + b = 36 ...( 2 )

Adding ( 1 ) and ( 2 ) : -

a - b = 4

a + b = 36

2a = 40

= > 2a = 40

= > a = 40 / 2

= > a = 20

Substituting the value of a in ( 1 ) :

= > 20 - b = 4

= > 20 - 4 = b

= > 16 = b

Hence the required numeric value of length of the garden is 20 m and width is 16 m.

Answer 2

Answer:

Please refer the attachment dear