half the perimeter of rectangular Garden whose length is 4 m more than its width is 36 M find the dimension of the garden
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Answered by
27
Let the width of the park be x
the length of the park =x+4
[2(l+b)]/2=36
(l+b)=36
x+4+x=36
2x+4=36
2x=36-4
2x=32
x=16
width =16m
length =20m
the length of the park =x+4
[2(l+b)]/2=36
(l+b)=36
x+4+x=36
2x+4=36
2x=36-4
2x=32
x=16
width =16m
length =20m
Answered by
9
Let the width be a x
Then length is x+4
A.t.q
1/2*2{l+b}=36
x+x+4=36
2x=32
x=16
Then length is 16+4=20
Then length is x+4
A.t.q
1/2*2{l+b}=36
x+x+4=36
2x=32
x=16
Then length is 16+4=20
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