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A truck starts from rest and rolls down a hill with constant ACCELERATION. it travel a distance of 400 meter in 20 second. find force when truck mass is 7 metric tonnes.
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Answered by
3
The truck starts from rest, so initial velocity = 0
Distance travelled = 400 m
Time taken = 20 s
We know the equation of motion, S = ut + ½ at2
400 = 0 + ½ a * (20)2
a = 2 m/s2
Now, mass = 7 metric tonnes
= 7 * 1000
= 7000 kg
So force = mass * acceleration
F = 7000 * 2
= 14000 N
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Answered by
7
Initial velocity of the truck, u = 0 m/s
Time taken, t = 20 s
Distance covered by the stone, s = 400 m
According to the second equation of motion:
s = ut + 1/ 2 at 2
We have
400 = 0 × 20 + 1 /2 × × (20) 2
⇒ 400 = 200
⇒ = 2 m/s2
Now, Force = mass × acceleration
⇒ F = 7000 × 2 = 14000 N
Time taken, t = 20 s
Distance covered by the stone, s = 400 m
According to the second equation of motion:
s = ut + 1/ 2 at 2
We have
400 = 0 × 20 + 1 /2 × × (20) 2
⇒ 400 = 200
⇒ = 2 m/s2
Now, Force = mass × acceleration
⇒ F = 7000 × 2 = 14000 N
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