halp me answer this question
1-z to z - 1
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Answer:
Step-by-step explanation:
|z| = 1
Solution :
Let z = x + iy. Then,
z−1z+1=(x−1)+iy(x+1)+iy×(x+1)−iy(x+1)−iy=(x2+y2−1)+(x+y)i(x+1)2+y2
Now, z−1z+1 is purely imaginary ⇔x2+y2−1=0⇔x2+y2=1⇔|z|=1
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