Question

Halpp mee plss! I'll give Brainiest

Answer 1

Answer:

3)3.angle ACB=angle CBD

4.BC is common lenght

4) GH=JH

angle FJH=angle FGH

FH is common

there fore both ∆'s are congruent

Answer 2

[ 1 ]

GIVEN :-

• ∆ABC and ∆DCB are right triangle.
• AB = DC.

TO PROVE :-

• ∆ABC ≅ ∆DCB.

SOLUTION :-

In ∆ABC and ∆DCB,

→ AB = DC. [ Given ]

→ ∠ABC = ∠DCB. [ Perpendiculars ]

→ BC = BC. [ Common ]

.°. By "SAS" criteria of congruency ∆ABC ≅ ∆ADC

[ 2 ]

GIVEN :-

• ∆FGH and ∆FJH are right triangle.
• GH = JH

TO PROVE :-

• ∆FGH ≅ ∆FJH.

SOLUTION :-

In ∆FGH and ∆FJH,

→ GH = JG. [ Given ]

→ ∠FGH = ∠FJG. [ Perpendiculars ]

→ FH = FH. [ Common ]

.°. By "SAS" criteria of congruency ∆FGH ≅ ∆FJH.