Question

Hamad's house is shaped like a rectangle and it has a perimeter of 46m.find the length of the house if its width is 11cm

Answer 1

Answer:

Breadth is 11cm

Perimeter is 4600cm

P=2*(l+b)

4600=2*(L+11)

4600=22*L

4600/22=L

L=2whole number 22 /29

Answer 2

Answer:

length (l) = 22.89m

Step-by-step explanation:

The perimeter of rest angle - P = 2(l+W)

given P= 46m

= 46X100cm

width= 11cm/0.11m

46= 2(l+0.11)

46/2=(l+0.11)

23=l+0.11

23-0.11 = l

length = 22.88m