Hamad's house is shaped like a rectangle and it has a perimeter of 46m.find the length of the house if its width is 11cm
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Answered by
0
Answer:
Breadth is 11cm
Perimeter is 4600cm
P=2*(l+b)
4600=2*(L+11)
4600=22*L
4600/22=L
L=2whole number 22 /29
Answered by
0
Answer:
length (l) = 22.89m
Step-by-step explanation:
The perimeter of rest angle - P = 2(l+W)
given P= 46m
= 46X100cm
width= 11cm/0.11m
46= 2(l+0.11)
46/2=(l+0.11)
23=l+0.11
23-0.11 = l
length = 22.88m
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