Question

hameed has built a cubical water tank whit lid for his house whit each outer edge 1.5m long he gets the outer surface of the tank excluding the base coverd whit square tiles of side 25 find how much he would spend for the tiles if the cost of the tiles id ₹ 360 per dozen

Answer 1

Answer:Rs. 5400

Step-by-step explanation:

TSA of cube without base is 5a^2

a=1.5m

5a^2=5*1.5*1.5=11.25m^2

Area of one tile =s*s

S=0.25m

0.25*0.25=0.0625m^2

No.of tiles=11.25/0.0625=180 tiles

Cost of 12 tiles =360

Cost of 1 tile = 30

Cost of 180 tiles = 180*30

=Rs5400

Answer 2

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Since Hameed is getting the five outer faces of the tank covered with tiles, he would need to know the surface area of the tank, to decide on the number of tiles required.

Edge of the cubical tank = 1.5m = 150cm (=a)

So, Surface area of the tank = $5\times150\times150cm^2$

Area of each square tile = side × side = $25\times25cm^2$

So, the number of tiles required =$\dfrac{surface\:area\:of\:the\:tank} {area\:of\:each\:tile}$=$\dfrac{5\times150\times150\times}{25\times25}$ = 180

Cost of 1 dozen tiles i.e.,cost of 12 tiles = ₹360

Therefore,Cost of 1 tile = ₹$\dfrac{360}{12}$=₹30

So, the cost of 180 tiles = 180 × ₹30 = ₹5400.