Question

Hameed has built a cubical water tank with lid for his house, with each other edge 1.5 m long. He gets the outer surface of the tank excluding the base, covered with square tiles of side 25 cm. Find how much he would spend for the tiles, if the cost of tiles is Rs. 360 per dozen.​

Answer 1

Answer:

${ \bold{ \red{Given}}}$

• Hameed has built a cubical water tank with lid for his house, with each other edge 1.5 m long
• Outer surface of the tank excluding the base, covered with square tiles of side 25 cm

${ \bold{ \pink{Find}}}$

• How much he would spend for the tiles, if the cost of tiles is Rs. 360 per dozen.

${ \bold{ \purple{Solution}}}$

Area of five faces (other than the base) of the tank = 5×(1.5) ²m²

${ \to{5 \times {(1.5)}^{2}cm }}$

${ \to{5 \times {150}^{2} }}$

Area of each square tile =25×25cm²= 625 cm²

${ \boxed{ \sf{no.of \: \: tiles = \frac{area \: \: of \: \: five \: \: faces}{area \: \: of \: \: each \: \: tile} }}}$

${ \to{ \frac{5 \times {150}^{2} }{625} }}$

${ \to{180}}$

${ \to{ \frac{180}{12} = 15}}$

So,the cost of the tiles at the rate of Rs. 360 per dozen =Rs.15×360=Rs.5400

Answer 2

Given:

⠀⠀⠀⠀

• Hameed built a cubical water tank with lid for his house.
• Length of each other edge = 1.5 m
• He gets the outer surface area of the tank excluding the base, covered with square tiles of side 25 cm.
• Cost of tiles per dorzen = 360 Rs

⠀⠀⠀⠀

To find:

⠀⠀⠀⠀

⠀Money spend for the tiles.

⠀⠀

Solution:

⠀⠀

According to the question,

Area of five faces(other than the base) of the tank

= 5 × (1.5)$^{2}$ m$^{2}$

= 5 × 150 × 150 cm$^{2}$

Area of each square tile = l × b

= 25 × 25 cm$^{2}$

Hence, required number of tiles = Area of five tiles ÷ Area of a tile

$\frac{5 \times 150 \times 150}{625} \\ \\ = 180$

180/12 dozens = 15 dozens

cost of tiles was Rs 360 per dozen.

So, the cost of required tiles at the rate if Rs 360 per dozen = 15 × 360

= 5400 Rs