Hameed has built a cubical water tank with lid for his house, with each outer edge 1.5 m long. He gets the outer surface of the tank excluding the base, covered with square tiles of side 25 cm Find how much he would spend on the tiles if the cost of the tiles is Rs.360 per dozen.
Answers
Here is the answer to your question.
Given :-
• Hamid has built a water tank with lid for his house, with each other edge is 1.5m long
• He gets the outer surface of the tank excluding the base, covered with square tiles of side 25cm
• The cost of the per dozen tiles is Rs360 .
Solution:-
Here,
The given length of the cubical tank from each side is 1.5m = 150cm
[ Convert m into cm that 1.5 * 100 = 150cm ]
Now,
It is given that the outer surface of the tank excluding the base, covered with square tiles of side 25cm. It means only 5 sides of cube covered with tiles.
Therefore,
As we know that,
TSA of cube = 6a^2
[ But here only 5 sides are covered ]
Therefore,
Surface area of cubical water tank
= 5 * a^2
Put the required values,
Surface area of cubical water tank
= 5 * 150 * 150 = 750 * 150 = 112500
Now ,
The given side of square tile is 25cm
Therefore ,
Area of square tile = 25 * 25
Area of square tile = 625 cm^2
According to the question,
Number of square tile cover five side of the cubical tank = TSA of cubical water tank excluding the base / Area of tiles.
Put the required values,
Number of square tile cover five side of cubical tank = 112500/625 = 180 tiles
Now,
The cost of one dozen tiles = Rs 360
Therefore
Total cost of tiles = 180/12 * 360
Total cost of tiles = 180 * 30 = Rs5400