Question

Hamid has 3 boxes of different fruits.The box A weigs 5/2 kg more than box B.Box C weighs 41/4 kg more than box B.The total weight is 48 whole 3/4kg.How many kg does box A weighs? ​

Answer 1

GiVeN :

• Box A weighs 5/2 kg more than Box B

• Box C weighs 41/4 kg more than Box B

• Total weight of boxes is $\sf\: 48 \dfrac{3}{4}$ kg

To FiNd :

• The Weight of Box A

SOluTiOn :

Let the weight of Box A be x kg.

$\textbf{\underline{\underline{According\:To\:Question:}}}$

$\star \: \sf \: Weight \: of \: box \: A = x + \dfrac{5}{2} kg...(i)$

$\star \: \sf \: Weight \: of \: box \: C = x + \dfrac{41}{4} kg$

$\star\sf Total \: Weight \: = (x + \dfrac{ 5}{2} + x + x + \dfrac{1}{4}) \: kg$

Given Total Weight of boxes = 195/4 kg

$\therefore \sf \: x + \dfrac{5}{2} + x + x + \dfrac{41}{4} = \dfrac{195}{4}$

$\rightarrow \sf \: 4x + 10 + 4x + 4x + 41 = 195$

$\rightarrow \sf \: 12x + 51 = 195$

$\rightarrow \sf \: 12x = 195 - 15$

$\rightarrow \sf \: 12x = 144$

$\rightarrow \sf \: x = \dfrac{144}{12}$

$\rightarrow \sf \: x = \large \boxed{ \sf \: 12}$

Putting x = 12 in (i),we get :

$\star \: \sf \: Weight \: of \: box \: A =( 12 + \dfrac{5}{2} )kg$

$\rightarrow \sf \: \dfrac{24 + 5}{2} = \dfrac{29}{2} = 14.5 \: kg$

Hence, Weight of The Box A = 14.5 kg

Answer 2

$\huge \boxed{ \fcolorbox{cyan}{grey}{refer \: to \: attachment : }}$

$\bf \underline{i \: hope \: its \: help \: u}$