Question

hammer of mass 500 g, moving at 50 m s−1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?
​

Answer 1

Answer:

Explanation:

Mass of the hammer, M=500g =0.5kg

                    Initial velocity of the hammer, u=50 ms  

−1

 

                    Final velocity of the hammer, v=0

                    Time taken, t=0.01 s  

Thus change in momentum of the hammer, ΔP=mv−mu

 ΔP=0−0.5×50=−25  kg ms  

−1

 

Force of the nail on hammer, ∣F∣=  

t

∣ΔP∣

​  

=  

0.01

25

​  

=2500 N 4

Answer 2

Answer:

2500 Newton

Explanation:

Acceleration = change in velocity /time

= 50/0.01

= 5000 m/s²

Force = mass x acceleration

= 0.5 x 5000

= 2500 Newton