Question

Hammer of mass 500 gram moving at 15 metre per second strikes and nail the nail stop the hammer in a very short time of 0.01 second what is the force of the nail on the hammer

Answer 1

Answer:

- 750 N

Explanation:

Given :

Mass = 500 g or 0.5 kg

Initial velocity ( u ) = 15 m / sec

Final velocity will become zero i.e. 0 m / sec

Time  ( t ) = 0.01 sec

We have to find force :

We have ,

F = m a

a = v -u / t

a = - 15 / 0.01

a = - 1500

F = m a

F = 0.5 × - 1500

F = - 750 N

Since force is vector quantity negative sign show direction :

Hence we get answer.

Answer 2

Answer:-

F = -750N

Exlanation:-

Given:

• m = 500gm = 0.5kg
• u = 15 m/s
• t = 0.01
• v = 0

To Find:-

Force of nail on hammer

Solution:-

V = u + at

0 = 15 + a(0.01)

-a(0.01) = 15

$\bold{a = -1500m{s}^{-2}}$

Now,

F = ma

F = 0.5 × -1500

$\bold{F= -750N}$