Question

Hammer weighing 1.5 kg and moving at a speed of 10m/s strikes a nail driving it into a wooden block. The duration of impact is 0.005 seconds. Find the average impact force and the distance of

Answer 1

m=1.5kg

u=10m/s

v=0

t=0.005 s

a=v-u/t

=0-10/0.005

=-10/0.005

=-2000$m/s^{2}$

F=ma

=1.5*-2000

=-3000N

$v^{2} -u^{2}$=2as

0-10*10=2*-2000*s

-100=-4000s

s=-4000/-100

=40 m

Answer 2

average impact force 1200N opposite direction of velocity of hammer and distance of penetration is 4 cm