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AR.V. has following probability distribution .x: 012 3 4 5 6 p(x): k 2k 3k 5k 4k 2k k The value of k is --
O 2.19
O 1/18
O 1/17
01/16
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Answer:
value of k is 1/16 ok
Step-by-step explanation:
bhai
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