Question

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Answer 1

Answer:

Step-by-step explanation:

Given : cosecθ−sinθ=a3 and secθ−cosθ=b3

⇒sinθ1−sinθ=a3

⇒sinθcos2θ=a3

⇒a=(sinθcos2θ)31

Similarly ; b=(cosθsin2θ)31

⇒a2b2(a2+b2)=a4b2+a2b4

⇒(sinθcos2θ)34(cosθsin2θ)

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