Question

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dolve this question
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Answer 1

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Answer 2

Answer:

Let A(t22,2t2),B(t12,2t1) be the two points on the parabola.

AB is the diameter of the circle.

Let C be the centre of the circle.

⟹C≡(2t12+t22,t1+t2)

The axis of the parabola is X−axis

So, the circle touches the X−axis

Hence, distance of C from X−axis= radius of circle

⟹∣t1+t2∣=r

⟹(t1+t2)=±r

Slope of AB=x2−x1y2−y1

=t12−t222t1−2t2

=