Question

☆☆HAPPY INDEPENDENCE DAY ☆☆

HERE'S YOUR QUESTION

Five years ago, Ananya's mother was 5 times as old as Ananya. If her mother is now three times as as old as Ananya, find their present ages. ​

Answer 1

Answer:

Step-by-step explanation:

Ananya's age=x

Her mom's age=3x

5years ago

Ananya's age=x-5

Her mom's age=3x-5

5(x-5)=3x-5

5x-25=3x-5

2x=20

x=10

So the present ages are:-

Ananya's=10 yrs

Her mom's=10*3=30yrs.

Answer 2

Answer:

Let the present age of Ananya be x years and the present age of Ananya's mother be 3x years.

Then, five years ago :

Ananya's age would be (x - 5) years

And her mother's age would be (3x - 5) years

A/q, (3x - 5) = 5(x - 5)

3x - 5 = 5x - 25

25 - 5 = 5x - 3x

20 = 2x

So, 2x = 20

x = 20/2

x = 10 years

Therefore, Ananya's present age = x = 10 years

Her mother's present age = 3x = 30 years

Hope it is helpful for you...