Math, asked by Anonymous, 11 months ago

☆☆HAPPY INDEPENDENCE DAY ☆☆


HERE'S YOUR QUESTION


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Answered by SaI20065
76

\small{\underline{\rm{\red{Let,\:the\: present\: age\: of \:Raju\: be\: x\:}}}}

\small{\underline{\rm{\red{And\: present\: age\: of\: Peter\: be\: y\:}}}}

\small\bold{Then,}

\small\bold{According\: to\: the\: quastion\:}

\small{\underline{\rm{\red{5 years\: ago\: Raju\: was\: twice\: as old\: as Peter\:}}}}

\bold{So, x-5 = 2(y-5)}[/tex)</p><p></p><p>[tex]\bold{x-5 = 2y - 10}

\bold{x - 2y = - 5 …(1)}

\small{\underline{\rm{\red{now, \:5 years\: later\:}}}}

\small{\underline{\rm{\red{Raju\: age \:will\: be\: 5\: years\: more\: than\: peter\:}}}}

\bold{So, x+5 = (y+5) +5}

\bold{x+5 = y + 10}

\bold{x - y = 5 …(2)}

\small\bold{Now,\: solving\: equation (1) \:and (2)\:}

\bold{x - 2y = - 5 and}

\bold{x - y = 5, we get}

\bold{y = 10 and x = 15}

\small\bold{present age of Raju = 15}

\small\bold{present age of peter = 10}

{\small{\boxed{\underline{\mid{\red{x= 15, y= 10}}}}}}

Answered by Anonymous
3

Ye dekho

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