Question

Happy new year guys ❤<br /><br />Two blocks of masses 10kg and 30kg are placed along a vertical line . the first is raised through a height of 7cm . by what distance should the second mass be moved to raise the centre of mass 1cm ? <br />

Answer 1

As ycm = m1 y1 +m2y2)/m1 + m2

So 1 = 10(7) + 30 y2)/10+30

40 = 70 + 30 y2

30 y2 = 40 -70

30 y2 = -30

y2 = -1

therefore it should be raised downward by 1 cm

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer....

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m₁=10 kg                 m₂= 30 kg
y₁ = 7cm                   y₂ = ?

The centre of mass is raised by 1 cm.

Centre of mass = (m₁y₁+m₂y₂) / (m₁+m₂)

1 = (10x7₁+30y₂) / (10+30)

1 = (70+30y₂) / 40

40 = 70+30y₂

30y₂ = -30

y₂ = -1

So , m₂ = 30 kg body should be displaced 1 cm downward so , as to raise the centre of mass through 1 cm.
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