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Prove that 3 + √5 is an irrational number.
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Let us assume that 3 + √5 is a rational number
where, b≠0 and a, b are integers
∵ a, b are integers ∴ a – 3b is also integer
is rational which cannot be possible
∵
which is an irrational number
∵ it is contradicting our assumption ∴ the assumption was wrong
Hence, 3 + √5 is an irrational number
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