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16x²-17z+z² factorise
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AnswerZ^2 - 17z +16
Now, Factorising,
=> z² - 2× 4z × 2 + 2² - 2²+ ( 4 ) ²
=> ( z - 2 )² - 2² +4²
=> ( z - 2 )² - 4 +16
=> ( z - 2 )² - 12
By using identity,
[ a ² - b ² = ( a + b ) ( a - b )]
=> ( z- 2 )² - ( √12 )²
=> ( z - 2 - √12 ) ( z - 2 + √12 )
Answered by
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Answer:
Happy Rakshabandhan to you too!
16x² - 17z + z² ; factorize equals to ;
There is only one easy step to solve this question ;
take out common factors ;
you will get this ;
16x²-17z + z²⇔ 16x² - 20z -3z + z²
↓ ↑
4[4x² - 5z ] z[ -3 + z ]
Those are the factors ;
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