Question

har ka parimeykaran√5+√2​

Answer 1

Answer:

5 / √(3 - √5) = (15 + 5√5)(√(3 - √5)) / 4

Step-by-step explanation:

we are given that

5 / √(3 - √5)

Multiplying and dividing by √(3 - √5) we get

5(√(3 - √5)) / (√(3 - √5))²

= 5(√(3 - √5)) / (3 - √5)

Multiplying and dividing by (3 + √5) we get

= 5(3 + √5)(√(3 - √5)) / 9 - 5

= 5(3 + √5)(√(3 - √5)) / 4

= (15 + 5√5)(√(3 - √5)) / 4

= (15 + 5√5)(√(3 - √5)) / 4

So

5 / √(3 - √5) = (15 + 5√5)(√(3 - √5)) / 4

And right hand side has denominator free of radical

Answer 2

Answer:

they can't add because they are under the root