Question

हरिहर काका को जबरन उठाकर ले जाने वाले लोग कौन थे उन्होंने उनके साथ कैसा व्यवहार किया
$6 \times { \frac{}{?} }^{2}$
​

Answer 1

Answer:

Given :

Initial velocity (u) = 0 m/s

Final velocity (v) = 18 km/h

Time (t) = 5 sec

To Find :

Acceleration of the car.

The distance covered by the car in that time.

Solution :

First convert km/h into m/s.

\begin{gathered} : \implies \: \: \: \: \sf \: Final \: velocity = \frac{18 \times 5}{18} \\ \\ \\ : \implies \: \: \: \: \sf \: Final \: velocity = \: 5 \: m s\end{gathered}

:⟹Finalvelocity=

18

18×5

:⟹Finalvelocity=5ms

$\begin{gathered} : \implies \: \: \: \boxed{ \green{ \sf \: v = u + at}} \\ \end{gathered}$

:⟹

v=u+at

Substitute all values :

\begin{gathered} : \implies \: \: \: \sf \: 5 = 0 + a \times 5 \\ \\ \\ : \implies \: \: \: \sf \: \: 5a = 5 \\ \\ \\ : \implies \: \: \: \sf \:a = \cancel{ \frac{5}{5} } \\ \\ \\ : \implies \: \: \: \sf \: \: a = 1 \: {ms}^{2} \end{gathered}

:⟹5=0+a×5

:⟹5a=5

:⟹a=

5

5

:⟹a=1ms

2

\begin{gathered} : \implies \: \: \: \boxed{ \pink{ \sf \: s= ut + \frac{1}{2} a {t}^{2} }} \\ \\ \end{gathered}

:⟹

s=ut+

2

1

at

2

Substitute all values :

\begin{gathered} : \implies \: \: \: \sf \: s= 0 \times 5 + \frac{1}{2} \times 1 \times {5}^{2} \\ \\ \\ : \implies \: \: \: \sf \: s= \frac{1}{ \cancel{2} } \times \cancel{ 25 }\\ \\ \\ : \implies \: \: \: \sf \: s= \: 12.5 \: m\end{gathered}

:⟹s=0×5+

2

1

×1×5

2

:⟹s=

2

1

×

25

:⟹s=12.5m

Hence,Solved !!