Hari and Nina each have a cylinder. Hari’s cylinder has a diameter of 6 cm and height
of 8 cm. Nina’s cylinder has a diameter of 8 cm and height of 6 cm. Whose cylinder has
larger surface area?
Answers
Answer:
Hari's cylinder :
Diameter = 6cm
Radius = 6/2 = 3 cm
Height = 8 cm
Surface area = (2 × 22/7 × 3 × 8) + (2 × 22/7 ×{3}^2)
= (1056/7) + (396/7)
= 150.85 + 56.57
= 207.42 cm
Nina's cylinder :
Diameter = 8 cm
Radius = 8/2 = 4 cm
Height = 6 cm
Surface area = (2 × 22/7 × 4 × 6) + (2 × 22/7 × {4}^2)
= (1056/7) + (704/7)
= 150.85 + 100.57
= 251.42 cm
Therefore, Nina's cylinder has larger surface area.
Ans. Nina's cylinder has larger surface area.
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Answer:
Naina's cylinder has larger surface area
Step-by-step explanation:
surface area of cylinder=2πr(h+r)
hari's cylinder=2*(22/7)*3(3+6)
=20.72mm
naina's cylinder=2×π×4(4+6)
=25.12mm
hence naina's cylinder has larger surface area