Math, asked by kannan82gmr, 5 months ago

Hari and Nina each have a cylinder. Hari’s cylinder has a diameter of 6 cm and height

of 8 cm. Nina’s cylinder has a diameter of 8 cm and height of 6 cm. Whose cylinder has

larger surface area?​

Answers

Answered by Sanju1534
2

Answer:

Hari's cylinder :

Diameter = 6cm

Radius = 6/2 = 3 cm

Height = 8 cm

Surface area = (2 × 22/7 × 3 × 8) + (2 × 22/7 ×{3}^2)

= (1056/7) + (396/7)

= 150.85 + 56.57

= 207.42 cm

Nina's cylinder :

Diameter = 8 cm

Radius = 8/2 = 4 cm

Height = 6 cm

Surface area = (2 × 22/7 × 4 × 6) + (2 × 22/7 × {4}^2)

= (1056/7) + (704/7)

= 150.85 + 100.57

= 251.42 cm

Therefore, Nina's cylinder has larger surface area.

Ans. Nina's cylinder has larger surface area.

Hope it will help you. Plz thanks the ans and mark as brainliest if it is helpful to you.

Answered by bavana64
0

Answer:

Naina's cylinder has larger surface area

Step-by-step explanation:

surface area of cylinder=2πr(h+r)

hari's cylinder=2*(22/7)*3(3+6)

=20.72mm

naina's cylinder=2×π×4(4+6)

=25.12mm

hence naina's cylinder has larger surface area

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