Question

Hari and teja won a lottery which they agreed to share in ratio of 5 :3 teja recived :150 how much hari recived ?what is total amount

Answer 1

Solution:

Given:

The ratio of Hari and Teja=5:3

Amount received by Teja=150

Let:

Their ratio of amount be X

The amount received by Hari=5x

The amount received by Teja=3x

A.T.Q

==>3X=150

==>X=150/3

==>X=50

Therefore,

The amount received by Hari

==>5x

==>5×50

==>250

Hence,

The total amount=Hari's A+ Teja's A

=250+150=>400

Answer 2

↪Question :-

• Hari and Teja won a lottery which they agreed to share in the ratio of 5:3, Teja recived Rs 150 how much Hari recived ?What is total amount?

↪Solution :-

Given :

• Share in the ratio = 5:3
• Amount received by Teja = Rs 150

To Find :

• Amount received by Hari.
• Total Amount.

Let the amount received by Hari and Teja be Rs 5x and Rs 3x.

$\tt{\therefore {3x = 150}}$

$\sf{ : \implies{3x = 150}} \\ \\ \sf{ : \implies{x = \dfrac{150}{3} }} \\ \\ \sf{ : \implies{x = 50}}$

• Amount received by Hari:$\sf {Rs\:(5\times 50)= Rs\:250}$
• Total Amount:$\sf{Rs\:(250+150)=Rs\:400.}$

$\bf{\therefore {Amount\:received \:by\:Hari\: is\:Rs\:250. }}$

$\bf {\therefore{Total\: Amount\:is\:Rs\:400. }}$

$\rule{307}{2}$