Math, asked by ajayravat474, 3 days ago

Hari borrowed ₹ 800 at 12% interest per annum for 3 years. a) How much interest did he pay? b) What was the amount to be paid back at the end of 3 years?​

Answers

Answered by itzmedipayan2
4

Answer:

Principal = Rs 800

Interest rate=12%

Time=3 years

So first we need to solve for a.

So the formula is

 \frac{p \times r \times t}{100}  \\  \\  =  \frac{8 \cancel{00} \times 12 \times 3}{1 \cancel{00}} \\  \\  = 8 \times 12 \times 3 \\  = 96 \times 3 \\  = 288

a. He paid an interest of Rs 288

Now we need to solve for option b.

So

To find Amount, it is P+SI

=800+288

=1088

The amount he will get back at the end of 3 years is Rs 1088.

Hope it helps you from my side

Answered by amitnrw
2

He pays Rs 288 as interest and Amount to be paid back after 3 years = Rs 1088 if ₹ 800 borrowed at 12% interest per annum for 3 years.

Given:

  • Hari borrowed ₹ 800 at 12% interest per annum for 3 years

To Find:

  • a) How much interest did he pay?
  • b) What was the amount to be paid back at the end of 3 years?​

Solution:

  • SI = P * R * T /100
  • P + principal
  • R = rate of interest in % per annum
  • T = Time in Years
  • SI = Simple Interest
  • A = Amount
  • A = P + Interest

Step 1:

Substitute P = 800 , R = 12 and T = 3 to find Interest amount in 3 years

Interest = P * R * T/100

Interest = 800 * 12 * 3 /100

Interest = 8 * 36

Interest = 288  Rs

He pays Rs 288 as interest

Step 2:

Add interest Rs 288 in borrowed Rs 800 to find amount to be paid back

= 800 + 288

= 1088 Rs

Amount to be paid back after 3 years = Rs 1088

Hari pays Rs 288 as interest and Amount to be paid back after 3 years = Rs 1088 if ₹ 800 borrowed at 12% interest per annum for 3 years.

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