Question

Hari is twice as old as his son.Twenty years ago he was four times as old as the son.Find the present age of each

Answer 1

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Answer 2

$\huge\red{Answer}$

Let the present age of Hari be x yrs

And present age of son be y yrs

ATQ,

x = 2y --------------------(i)

20 yrs ago,

Hari's age = (x-20) yrs

Son's age = (y-20) yrs

=> (x-20) = 4(y-20)

=> x-20 = 4y-80

Putting the value of x

2y-20 = 4y-80

=> 2y-4y = -80+20

=> -2y = -60

=> 2y = 60

=> y = 30

x = 2y

= 2×30

= 60

HOPE IT HELPS YOU !!