Question

Hari walks from his home at 5km/hr and reaches his office 3 minutes too late the next day he increases his speed by 1km/per hr and reaches 3 min to early the distance of his office from hone is​

Answer 1

Given,

• Hari walks from his home at 5km/hr and reaches his office 3 minutes late.

• By increasing speed by 1km/per hr he reaches 3 min early.

To find,

The distance of his office from home

Solution,

Let the distance of his office be $a$ km.

Let the time taken to reach punctually = $t$

Now, with the speed of $5km/hr$, time taken is = $(t + 0.05)hr$

$5 = \frac{a}{t + 0.05} \\5t + 0.25 = a$ -------eq(1)

With speed increased by $1km/hr$, time taken is = $(t - 0.05)hr$

$6 = \frac{a}{t - 0.05}\\6t - 0.3 = a$ ----------eq(2)

From eq(1) and eq(2),

$a = 0.55km = 550m$

Therefore, the distance of his office from home is $550m.$

Answer 2

Answer:

The distance of his office from home is 3 km.

Step-by-step explanation:

As per the data given in the question,

We know,

$Distance=Speed\times Time$...........(i)

Given that,

Initial speed of Hari = 5 km/hr

Increased speed of Hari = 5+1= 6km/hr

Difference in reaching time = 3min+3min = 6 min=  $\frac{1}{10}$ hour

Let the distance of office to house be D

so, putting in (i) and relating it to time difference,

$\frac{D}{5} -\frac{D}{6} =\frac{1}{10}$                (As, $\frac{Distance}{Speed} =Time$)

$\frac{6D-5D}{30} =\frac{1}{10} \\\frac{D}{30} =\frac{1}{10}\\ D= \frac{1}{10} \times 30\\D= 3\: km$

So, the distance of his office from home is 3 km.

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