harihar kaka path dwara lekhak ne sanyukt parivar ke bare me jo kuch bataya hai kya aap usse sehmat hai? Apna tark dijiye
No spamm pls , it's of 5marks
Answers
Answer❣
Question :
An object travels 20m in 4s and then other 20m in 10s . What is the average speed of the object ?
Solution :
As per the question we have two cases so let's assume each as Case 1 and Case 2 respectively !
Case 1 :
Distance Covered : 20m
Time taken : 4 sec
Speed : Distance / time
: 20 / 4
: 5 m / sec
Case 2 :
Distance Covered : 20 m
Time taken : 10 sec
Speed : Distance / time
: 20 / 10
: 2 m / sec
huge average speed = total distance total time
averagespeed=totaltimetotaldistance
= \5 + 2 4 + 10=4+105+2
= 7 40 = 0.175=407=0.175
Hence , the average speed of the object is 0.175 m / sec !!
Answer:
Hey there
So let's solve your your problem step by step.
We know that
(a+b)^2=a^2 + b^2 + 2ab.
So
We already have values for LHS as 5 and value of ab as 3.
So,
(a+b)^2 =5^2 = 25
And, 2ab = 2*3 = 6
Now we substitute the values for both in general equation and we get,
25 = a^2 + b^2 + 6
a^2 + b^2 = 25 -6 = 19.
Therefore, the answer to your question is 19.