Math, asked by shagun1237, 1 year ago

Harish borrowed rupees 20000 from his friend at 12% per annum simple interest he lent it to Amit at the same rate but compounded annually find his gain after 2 years

Answers

Answered by nikitabakshi17
14

SI = P ×R× T /100

Therefore P 20000

R 12%

T 2 yr

SI =20000 ×12×2 /100

=4800

Attachments:
Answered by TheLostMonk
36
according to first statement :
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principal = Rs 20000 , rate = 12% ,

time = 2 yrs, since we know that ,

S.I = p × r × t / 100

=20000 × 12 × 2 / 100 = Rs 4800

Amount harish has return to his friend at simple interest

A1 = 20000 + 4800 = Rs 24800

according to second statement:
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he lent it to amit at the same rate of interest and time but compounded annually.

p = 20000, t = 2 yrs , r = 12 %

Find the Amount :
--------------------------
amount = p [ 1 + ( r/100) ]^t

=20000 [ 1 + ( 12 / 100 ) ]^2

=20000 ( 112/ 100 )^2

=20000× (112/ 100 ) × ( 112/100 )

=25088

A2 = 25088

Find the gain :
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gain = A2 - A1 = 25088 - 24,800

gain = Rs 288

therefore ,

his gain after 2 years = Rs 288

Answer : gain = Rs 288

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