Question

Harish divides two sums of money among his four sons Naresh, Vipin, Bhupesh, and Yogesh. The first sum is divided in the ratio 4 : 3 : 2 : 1 and second in the ratio 5 : 6 : 7 : 8. If the second sum is twice the first, then the largest total is received by​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The largest total is received by Naresh.

Step-by-step explanation:

Given,Harish divides two sums of money among his four sons Naresh, Vipin, Bhupesh, and Yogesh.

The first sum is divided in the ratio 4 : 3 : 2 : 1.

and second in the ratio 5 : 6 : 7 : 8.

Let first sum be x rupees and second sum be y rupees.

It is given that the second sum is twice the first.

So,$y = 2x$

From first sum,

Naresh gets

$x \times \frac{4}{4 + 3 + 2 + 1} \\ = x \times \frac{4}{10} \\ = \frac{2x}{5} \: rupees$

Vipin gets

$x \times \frac{3}{10} \\ = \frac{3x}{10} \: rupees$

Bhupesh gets

$= x \times \frac{2}{10} \\ = \frac{x}{5} \: rupees$

Yogesh gets

$= x \times \frac{1}{10} = \frac{x}{10} \: rupees$

From second sum,

Naresh gets

$= y \times \frac{5}{5 + 6 + 7 + 8} \\ = y \times \frac{5}{26} \\ = \frac{5y}{26} \: \\ = \frac{5 \times 2x}{26} \\ = \frac{5x}{13} \: rupees$

Vipin gets

$= y \times \frac{6}{26} \\ = \frac{3y}{26} \\ = \frac{3 \times 2x}{26} \\ = \frac{3x}{13} \: rupees$

Bhupesh gets

$= y \times \frac{7}{26} \\ = \frac{7y}{26} \\ = \frac{7 \times 2x}{26} \\ = \frac{7x}{13} \: rupees$

Yogesh gets

$= y \times \frac{8}{26} \\ = \frac{4y}{13} \\ = \frac{4 \times 2x}{13} \\ = \frac{28x}{13} \: rupees$

So, Naresh gets total

$= \frac{2x}{5} + \frac{28x}{13} \\ = \frac{26x + 140x}{65} \\ = \frac{166x}{65} \: rupees$

Vipin gets total

$\frac{3x}{10} + \frac{3x}{13} \\ = \frac{39x + 30x}{130} \\ = \frac{69x}{130} \\ = \frac{ \frac{69x}{2} }{65} \\ = \frac{34.5x}{65} \: rupees$

Bhupesh gets total

$= \frac{x}{5} + \frac{7x}{13} \\ = \frac{13x + 35x}{65} \\ = \frac{48x}{65} \: rupees$

Yogesh gets total

$\frac{x}{10} + \frac{28x}{13} \\ = \frac{13x + 280x}{130} \\ = \frac{293x}{130} \\ = \frac{146.5x}{65} \: \: rupees$

It is clear that,

$\frac{166x}{65 } > \frac{146.5x}{65} > \frac{48x}{65} > \frac{34.5x}{65}$

Naresh gets largest amount.

Sum of money related more maths,

1)https://brainly.in/question/48873196

2)https://brainly.in/question/9097825