harish has twice as manu sweet as dora. after eating 18 sweet each. shr has five times as many as dora. how many sweet and harish start with?
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Let no. of sweets with dora be = x
Therefore , no. of sweets with harish = 2x
A.T.Q ,
2x-18 = 5(x-18)
Solving this ... We get,
2x - 18 = 5x - 90
Now ,
2x - 5x = -90 + 18
-3x = -72
3x = 72 ( minus cancels out with minus )
X = 24
No. Of sweets with Harish = 2x ( stated above )
So, Harish starts with 2 * 24 = 48 sweets
Therefore , no. of sweets with harish = 2x
A.T.Q ,
2x-18 = 5(x-18)
Solving this ... We get,
2x - 18 = 5x - 90
Now ,
2x - 5x = -90 + 18
-3x = -72
3x = 72 ( minus cancels out with minus )
X = 24
No. Of sweets with Harish = 2x ( stated above )
So, Harish starts with 2 * 24 = 48 sweets
syedrehan:
thanx
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