Question

harish invests rs.12,500 for 2years at 12p.a., calculate the amount and the compound interest that harish will get after 2 years.​

Answer 1

Answer:

amount =12500×(1+12/100)2

=12500×28/25×28/25

=15680

Answer 2

Given :-

• Principal = Rs,12500
• Rate = 12%
• Time = 2 year

To Find :-

• Compound Interest

Solution :-

${:} \longrightarrow \sf{\sf{Amount \: = \: Principal \: \times \: \bigg(\:1\: + \:\dfrac{Rate}{100}\:\bigg)^{Time}}}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: 12500\: \times \: \bigg(\:1\: + \:\dfrac{12}{100}\:\bigg)^{2}}}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: 12500\: \times \: \bigg(\:\dfrac{112}{100}\:\bigg)^{2}}}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: 12500\: \times \: \dfrac{112}{100}\: \times \: \dfrac{112}{100}}}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: 125\cancel{00}\: \times \: \dfrac{112}{1\cancel{00}}\: \times \: \dfrac{112}{100}}}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: \dfrac{ 125\: \times \: 112 \: \times \: 112}{100} }}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: \dfrac{ 14000 \times \: 112}{100} }}\\\\ {:} \longrightarrow \sf{\sf{Amount \: = \: \dfrac{ 1,568,000 }{100} }}\\\\ {:} \longrightarrow \sf{\bf{Amount \: = \:Rs,15680}}$

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$\longmapsto\sf \: Compound \: interest \: = \: Amount \: - \: Principal \\ \\ \longmapsto\sf \: Compound \: interest \: = \: 15680 \: - \: 12500 \\ \\ \longmapsto \sf \boxed{\bf { Compound \: interest \: = \: Rs,3180}}$

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Therefore, Compound Interest is Rs,3180

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