Question

Harish sold an article for 4200, at a loss of 16%. Find the cost price of the article.​

Answer 1

Answer:

CP will be 5,00 rupees

Step-by-step explanation:

CP = (100×sp)/100-loss%)

=420000/84

=₹5000.

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Answer 2

The cost price of the article = Rs. 5000

Given :

Harish sold an article for Rs. 4200, at a loss of 16%.

To find :

The cost price of the article

Solution :

Step 1 of 2 :

Form the equation to calculate cost price of the article

Let cost price of the article = Rs. C

Since Harish sold an article for Rs. 4200, at a loss of 16%.

So by the given condition is

$\displaystyle \sf C - \bigg[C \times \frac{16}{100} \bigg] = 4200$

Step 2 of 2 :

Calculate cost price of the article

$\displaystyle \sf C - \bigg[C \times \frac{16}{100} \bigg] = 4200$

$\displaystyle \sf{ \implies } C - \frac{16C}{100} = 4200$

$\displaystyle \sf{ \implies } \frac{100C - 16C}{100} = 4200$

$\displaystyle \sf{ \implies } \frac{84C}{100} = 4200$

$\displaystyle \sf{ \implies } C = 4200 \times \frac{100}{84}$

$\displaystyle \sf{ \implies } C = 5000$

Hence cost price of the article = Rs. 5000

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