Question

Harmonic oscillation is represented by y 0.34cos (300t+ 0.74), where y and t are in m and srespectively. Find its amplitude ,frequency and initial phase solution

Answer 1

The amplitude = 0.34 m

Frequency of oscillation = 47.75 Hz

initial phase = 0.74

-For a harmonic oscillation of the form y = A.cos( wt ± φ )

   A is the amplitude of oscillation

   w is the angular velocity given by w=2.pi.f (f is the frequency )

   φ is the initial phase angle

-In our question, y= 0.34.cos (300t + 0.74)

-By comparing it with the general form,

we have,

     A=0.34 m

     f = w / 2.pi = 47.75 Hz

    φ = 0.74