Math, asked by prathampandey14, 1 year ago

Harpreet's motorbike is facing towards West. He turns left and drives 10 km and turns left again and drives 10 km. Then he turns right and drives 40 km. He turns right again and drives 30 km. lastly; he turns right and drives 50 km. How far is Harpreet from the starting point?

Answers

Answered by TooFree
6

Answer:

20 km


Step-by-step explanation:

See attached

Distance between Start Point and End Point = 30 - 10 = 20 km


Answer: Harpreet is 20 km away from the starting point.

Attachments:
Answered by abhi178
4
answer :- 20km

explanation :- this can be solved easily with help of diagram.
see figure , Let's assume that Harpreet starts from origin O .

He turns left and drives 10km , e.g.,OA = 10km[ see figure ]

then he turns left again and drives 10km. e.g.,AB = 10km [ see figure ]

then he turns right and drives 40km,
e.g., BC = 40km [ see figure ]

then he turns right again and drives 30km,
e.g., CD = 30km [ see figure ]

now finally he turns right and drive 50km,
e.g., DE = 50km

now, we have to find How far is Harpreet from the starting point.
indirectly question ask us, what is the displacement of Harpreet.

we know, displacement = final position - initial position

see figure, here it is clearly shown that final position is 20km above from x axis
and starting point is located at origin
so, initial position = 0

hence, displacement of Harpreet = 20km - 0km = 20km

hence, Harpreet is 20km far from the starting point.
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