Question

Harpreet tosses two different coins simultaneously (say, one is of Re 1 and other of Rs 2). What is the probability that he gets at least one head?

Answer 1

SOLUTION :  

Given : Two coins are tossed simultaneously (₹1 & ₹2)  

If two coins are tossed then the possible outcomes are : HT, HH, TT, TH

Total no. of possible outcomes = 4

Let E = Event of getting at least one head

Outcomes favourable to  E = HT, HH, TH

No. of favorable outcomes = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = ¾  

Hence, the required probability of getting at least one head is ,P(E) = ¾

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Answer 2

Answer:

Step-by-step explanation:

Given :-

When two coins are tossed together, the total number of outcomes = 4

Possible outcomes = (HH, HT, TH, TT)

To Find :-

Probability that he gets at least one head.

Formula to be used :-

P (H) = Number of favorable outcomes/Total number of possible outcomes

Solution :-

Let H be the event of getting at least one head.

Then, Number of favorable events, n(H) = 3(HT,HH,TH,)

Number of favorable outcomes = 3

P (H) = Number of favorable outcomes/Total number of possible outcomes

P (H) = 3/4

Hence, the probability that he gets at least one head is 3/4.

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