Has anyone have It was simran's first day at school that teacher suggested that it would be a good idea for each child to meet every other child in the class. the teacher said, "when you meet me shake hands and introduce yourself by name. " if there were seven children in the class how many total handshakes were there?
ankur5155:
hi mantu
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There are total 7 children
See for first child there would be 6 children available to handshake
Now for Second child there would be 5 children available as child has already shaken hand with first child
For 3 rd child 6 children available as child already has shaken hand with 2 children
So on...
for 6 th children only 1 handshake as 5 handshake already done
So
6 +5+4+3+2+1 = 21 total handshakes
Or
As there are 7 children
here to have handshake 2 needs to be selected
So 7C2 would give no of ways 2 students can be selected out of 7
= 7! /2! (7-2)!
= 7!/2!(5!)
= 7× 6× 5!/ 2 × 5!
= 7× 6/2 .
= 7× 3
= 21
See for first child there would be 6 children available to handshake
Now for Second child there would be 5 children available as child has already shaken hand with first child
For 3 rd child 6 children available as child already has shaken hand with 2 children
So on...
for 6 th children only 1 handshake as 5 handshake already done
So
6 +5+4+3+2+1 = 21 total handshakes
Or
As there are 7 children
here to have handshake 2 needs to be selected
So 7C2 would give no of ways 2 students can be selected out of 7
= 7! /2! (7-2)!
= 7!/2!(5!)
= 7× 6× 5!/ 2 × 5!
= 7× 6/2 .
= 7× 3
= 21
Answered by
3
Answer:
Step-by-step explanation:
We know that for a handshake,we need two people.
We need to select two people from a group of 7.
Applying the concept of combinations,Number of ways of selecting two children out of 7=7C2= 7!/(2! * 5!)=21
Hence, number of handshakes=21
Hope you understood
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