Question

has one
rout &=1, find the
3
(3) 3x² - kx + 7 = 0 has
value of k​

Answer 1

p(x)=3x2-kx+7=0

p(1)=3*1²-1k+7=0

= 3-k+7=0

=10-k=0

=-k=10

k=-10