Question

has the shape of parallelogram whose base is 24 cm and the corresponding height is 10 cm how many such tiles are required to cover a floor of area 1018 square ​

Answer 1

$\huge{\underline{\underline{\red{\mathfrak{AnSwEr :}}}}}$

GivEn :

• Height of Parallelogram (h) = 20 cm
• Base of Parallelogram (b) = 24 cm

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To FinD :

• How many tiles are required to cover floor of Area 1018 cm² or

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SolutioN :

As we know that Area of Parallelogram is :

$\large{\boxed{\sf{Area \: = \: Base \: \times \: Height}}} \\ \\ \implies {\sf{Area \: = \: 24 \: \times \: 10}} \\ \\ \implies {\sf{Area \: = \: 240}} \\ \\ {\underline{\sf{\therefore \: Area \: of \: Parallelogram \: is \: 240 \: cm^2}}}$

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No. of tiles required :

$\large{\boxed{\sf{No. \: of \: tiles \: = \: \dfrac{Area \: of \: Floor}{Area \: of \:Tiles}}}} \\ \\ \implies {\sf{No. \: of \: tiles \: = \: \dfrac{1018}{240}}} \\ \\ \implies {\sf{No. \: of \: tiles \: = \: 4.24}} \\ \\ {\underline{\sf{\therefore \: No. \: of \: tiles \: required \: is \: 4}}}$

Answer 2

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

$\huge\purple{24 \times 10}$

$\huge\purple{240 {cm}^{2} }$

$\huge\purple{0.024 {m}^{2} }$

$\red{no. \: of \: tiles \: = \frac{area \: of \: room}{area \: of \: one \: tile} }$

$\huge\orange{ \frac{1080}{0.024} }$

$\pink{so... \: 45000 \:tiles \: are \: needed }$