Question

Hasan buys 2 kinds of clothes material for school uniforms,shirt material that cost him ₹50 per meter and trouser Material that cost him ₹90 per meter,, for every 3 meters of the shirt material,he buys 2 meters of the trouser Material he sells the material at 12% and 10% profit respectively,his totally sale is ₹36,600, how muchh trouser did he buy​

Answer 1

Answer:

Let ratio between shirt material and trouser material be 3x:2x3x:2x.

The cost of shirt material = 50\times3x=150x50×3x=150x

The selling price at 12% gain = \frac{100+P\%}{100}\times CP

100

100+P%

×CP

= \frac{100+12}{100}\times150x

100

100+12

×150x

= \frac{112}{100}\times150x=168x

100

112

×150x=168x

The cost of trouser material =

90\times2x=180x90×2x=180x

The selling price at 12% gain = \frac{100+P\%}{100}\times CP

100

100+P%

×CP

= \frac{100+10}{100}\times180x

100

100+10

×180x

= \frac{110}{100}\times180x=198x

100

110

×180x=198x

According to the question,

168x+198x=36,600168x+198x=36,600

\Rightarrow366x=36600⇒366x=36600

\Rightarrow x=\frac{36600}{366}=100⇒x=

366

36600

=100 meters.

Now, trouser material = 2x=2\times1002x=2×100

= 200 meters

Hence, Hasan bought 200 meters of the trouser material.