Question

Hasan buys two kinds of cloth material for school uniforms shirt material that costing Rs 50 of a better and trouser material that costume 95 metre for everything metre of his shirt materials he buys two middle of the trouser material is as the material of 12% and 10% profit respectively is total sale is 36,000 how much does a material ready by

Answer 1

Equations with linear expressions in one variable only are
known as linear equations in one variable.

 

An algebraic equation is an equality involving variables. It
has an equality sign(=). The expression on the left of the equality sign is the
Left Hand Side (LHS). The expression on the right of the equality sign is the
Right Hand Side (RHS).

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Solution:

Let
Hasan bought 2x m of trouser material and 3x m of the shirt material.

 

Per
metre selling price(S.P) of the trouser material = ₹90+90×12/100

= 90 + 1.2× 9

= 90 + 10.8

=₹100.80

 

Per
metre selling price(S.P) of trouser of shirt material

= ₹50+
50× 10/100

= ₹ 50 + 5

=₹55

 

Given: total amount of sale= ₹ 36660

100.80
x (2x) + 55 x (3x) = ₹36660

 

201.60
x + 165x = 36660

 

366.60
x  = 36660

 

X= 36660/366.60

x = 100

Trouser
material = 2x m = (2×100)m = 200m.

Hasan bought 200 m of trouser material.

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Answer 2

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