Question

Hasan buys two kinds of cloth materials for school uniforms, shirt material that
costs him 50 per metre and trouser material that costs him * 90 per metre. for every 3 metre of the shirt material he buys 2 metre of the trouser material. he sells the material at 12% and 10% profit respectively. his total sale is rupees 36600, how much trouser material did he buy?​

Answer 1

$~~~~~~~$$\bold{•}$$\underline\bold{Solution :-}$

$\sf{Hasan~buys~shirt~and~trouser~ in~ratio~2:3}$

$\sf{Let ~the~ ratio~ be~ x.}$

$\sf\color{red}{The~ cost ~of ~the~ shirt~ material~ :-}$

$~~~~~~~$$\bold{₹3x × 50 = ₹150x}$

$\sf\color{red}{The~ cost ~of ~the~ trouser ~material :-}$

$~~~~~~~$$\bold{₹2x × 90 = ₹180x}$

$\sf\color{red}{The ~selling ~price~ of ~the~ ~shirt~ material :-}$

$~~~~~~~$$\bold{150x+12~ of~ 150x}$

$\implies rs\quad\bigg\lgroup\bf 150x + \: \frac{12}{100} \: \times \: 150x \bigg\rgroup$

$\implies \: rs \: (150x \: + \: 18x) = rs \: 168x$

$\sf\color{red}{The~ selling~ price~ of ~the ~trouser ~material ~:-}$

$~~~~~~~$$\rm\underline{~180x +10~of~180x}$

$\implies rs\bigg\lgroup\bf 180x \: + \: \frac{10}{100} \: \times \: 180x \bigg\rgroup$

$\implies \: rs \: (180 x \: + \: 18x) = rs198x$

$\sf\color{red}{According ~to~ the~ Question :-}$

$~~~~~~~$$\rm\underline{168x + 198x = 36,660}$

$~~~~~~~$$\rm\underline{366x = 36,660}$

$x \: = \frac{36,660}{366}$

$\sf{100 ~(approx)}$

$\sf\color{red}{the~ trouser~ material~ bought ~by ~him}$

$\bold{•}$$\rm\underline{2×100m=200m}$