. Hasan buys two kinds of cloth materials for school uniforms, shirt material that
costs him 50 per metre and trouser material that costs him * 90 per metre. For every 3 meters of the shirt material he buy 2 meters of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is 36600 how much trouser material did he buy ?
Answers
Answer:
Step-by-step explanation:
Equations with linear expressions in one variable only are known as linear equations in one variable.
An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
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Solution:
Let Hasan bought 2x m of trouser material and 3x m of the shirt material.
Per metre selling price(S.P) of the trouser material = ₹90+90×12/100
= 90 + 1.2× 9
= 90 + 10.8
=₹100.80
Per metre selling price(S.P) of trouser of shirt material
= ₹50+ 50× 10/100
= ₹ 50 + 5
=₹55
Given: total amount of sale= ₹ 36660
100.80 x (2x) + 55 x (3x) = ₹36660
201.60 x + 165x = 36660
366.60 x = 36660
X= 36660/366.60
x = 100
Trouser material = 2x m = (2×100)m = 200m.
Hasan bought 200 m of trouser material.
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Hope this will help you